6.1.8 The following set of scores was obtained from a quiz: 4, 5, 8, 9, 11, 13, 15, 18, 18, 18, 20. The teacher computes the usual descriptive measures of central tendency and spread for these data and then discovers that an error was made. One of the 18s should have been a 16. Which of the following measures will NOT need to be changed from the original computations? (There may be more than one correct answer.) Mean Median Standard deviation IQR They all will need to be changed.

A. Mean
B. Median
C. Stndard Deviation
D. IQR
E. They will need to be changed

B. Median

D. IQ R

Step-by-step explanation:

from the given data :

mean = 12.6364 , median =13,

st. dev = 5.6262

Q3 = 18 , Q1 = 8

IQ R = Q3 - Q1 = 18-8 = 10

One of the 18s should be 16 then,

mean = 12.4545, median = 13,

st. dev = 5.4656

Q3 = 18 , Q1 = 8

IQ R = Q3 - Q1 = 18-8 = 10

So, median and IQ R will not need to be changed

these sign is used to tell weather the number is greater or less than the number   <   or >     but this sign means its equal =    

hope this you and

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752