Find the equation of the line passing through the point (6,3) that is perpendicular to the line 4x−5y=−10.

Step 1: Find the slope of the line 4x−5y=−10.
What would the perpendicular slope be?

Step 2: Use the slope to find the y-intercept of the perpendicular line.

Step 3: Write the equation of the line that passes through the point (6,3) that is perpendicular to the line 4x−5y=−10

Hi there! :)

Line passes through (6, 3) & perpendicular to 4x - 5y = -10

Step 1:

Identify the slope, In the slope-intercept form y=mx+b, we know that "m" is our slope.

We need to isolate y so we must first subtract 4x from both sides.

-5y = -4x - 10

Divide both sides by -5.

y = (-4x - 10)/-5

Simplify.

y = 4/5x + 2

"M" is simply a place mat so if we look at our given line, the "m" value is 4/5. Therefore, the slope for our given line is 4/5.

We need to note that we're looking for a line that's perpendicular to the given one. This means that our new line is the negative reciprocal of the given slope. This means that our new lines slope is -5/4.

Step 2:

Use point-slope form ( y-y₁=m(x-x₁) ) to complete our task of finding the y-intercept of our new line (which goes through 6,3).

y-y₁=m(x-x₁)

Let's start by plugging in -5/4 for m (our slope), 6 for x1 and 3 for y1.

y - (3) = -5/4(x - 6)

Simplify.

y - 3 = -5/4x + 5/6

Simplify by adding 3 from both sides.

y = -5/4x + 4 1/6

This can also be written as: y = -5/4x + 25/6

This means that step 2's answer is: the y-intercept is 25/6

Step 3's answer is:

y = -5/4x + 25/6

~Hope I helped!~

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted

goog may have it for you