How do you solve: 7^2=12^x

x = 1.566

Step-by-step explanation:

7^2=12^x

49 = 12^x

Exponential: b^x = y

Logarithmic: logb(y) = x.

logb(y) = x

log12(49) = x

Plug this in your calculator (on a TI-84, it's MATH -> A)

x = 1.566

x ≈ 1.57

Step-by-step explanation:

First, note that 7^2 equals 7 * 7 = 49. Now, we have:

49 =

In order to solve for x, we need to use logarithm, which basically "gets rid of" the exponent. What we need to do is take the of each side. Notice that the base of the logarithm is 12. This is because we want to cancel out the exponent base of 12 on the right side:

So, x ≈ 1.57.

Hope this helps!

srry idk

step-by-step explanation:

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841