The length of a rectangle is 5 5 centimeters less than six times six times its width. Its area is 14 14 square centimeters. Find the dimensions of the rectangle.

Dimensions of rectangle are length = 7 cm and width = 2 cm

Step-by-step explanation:

Let l = length and w = width of the rectangle.

Given that, length is 5 cm less than 6 times width. Rewriting it in equation form,

L =  6 w - 5  cm

Also given that area of rectangle is 14 cm²

Now using formula for area of rectangle,

Area of rectangle = length × width

Area of rectangle = l × w

Substituting the values,

14 = (6 w - 5) × w

Simplifying by using distributive rule,

14 = 6 w² - 5 w

To find the value of b, use the quadratic formula. So rewriting the equation in quadratic form ax²+bx+c=0

Subtracting 14 on both sides,

0 = 6 w² - 5 w - 14

Rewriting,

6 w² - 5 w - 14  = 0

Now applying quadratic formula,

Rewriting the formula in terms of w,

From the 6 w² - 5 w - 14  = 0, value of a = 6 , b = - 5 and c = - 14.

Substituting the values,

Simplifying,

Since √361 = 19,

There will be two values of w,

and

Simplifying,

and

and

Reducing the fraction in lowest form, divide first expression by 12 and second expression by 2.

and

Since the length of width cannot be negative, so value of w = 2 cm

To find the value of length, Use equation L =  6 w - 5  cm

L =  6 (2) - 5  cm

L =  12 - 5  cm

L =  7  cm

Therefore l = 7 cm and w = 2 cm are the dimensions of the rectangle.

.there can be infinite values of m and n that can satisfy the above equation. for each value of m of m or n. there maybe infinite sets of solution for the above

step-by-step explanation: