Which equation represents the volume of a cone with the same base and height as the cylinder below?

A cylinder with a height k and radius t.
Volume cone = pi t squared k
Volume cone = one-third pi t squared k
Volume cone = one-half pi t squared k
Volume cone = 3 pi t squared k

Volume cone = one-third pi t squared k

Step-by-step explanation:

Given a cylinder with a height k and radius t, the volume of the cylinder will be πt²k.

Since a come is carved out of the cylinder with the same base and height, the volume of the cone will be a fraction of that of the cylinder since part of the cylinder will be remaining. The volume of the come will be one-third of the volume of a cylinder. This is expressed as shown:

Volume of the cone = 1/3 of πt²k

Volume of the cone = 1/3πt²k

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer