Create a system of linear equations that when solved algebraically, prove to have no solution.
45 points
pls help

Basically, you just need to make them have the same slope, but a different y - intercept. That means they'll never intersect, so will have no solution.

Say one equation is

y = 3x + 5

That means the other can be something like

y = 3x + 6

Right? Because if

3x + 5 = 3x + 6

and you subtract 3x from both sides

5 = 6

which can't be true.

1. sometimes

2. never true

3. sometimes

step-by-step explanation:

these are pretty self explanatory if you know what supp right and com angles are