Polygon abcd transformed to create polygon a'b'c'd'. which transformation took place?

horizontal stretch by a factor of 2

translation 2 units to the right

dilation by a factor of 2

vertical stretch by a factor of 2

horizontal stretch by a factor of 1/2

The transformation that took place is:

horizontal stretch by a factor of 2

We are given that Polygon ABCD transformed to create polygon A'B'C'D'.

Clearly the polygon is first a translation of the polygon ABCD 1 units to the right and then it is horizontally stretched by a scale factor of 2.

since, the Length of the polygon was earlier 2 units and then the length of the Polygon A'B'C'D' are 4 units.

Hence, the transformation that took place in the Polygon ABCD is:

a horizontal stretch by a factor of 2

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step-by-step explanation:

9-15%

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47