Ba and bc are tangents to circle o at points a and c. if ba=7in and oa=3in, find the perimeter of quadrilateral OABC

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i believe that the answer is

b. y-1=-2(x-4)

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answer:   x*94 +688*6   = 267*100

94x+4128=26700    

94x=22572     /94

x=240.128

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