What is the substrate concentration [S] when the Vo is 1/4 Vmax? Hint: start with Vo = (Vmax * [S]) / (Km + [S]) substitute in for the Vo and solve for [S]

Step-by-step explanation:

Given that,

Vo = ¼ Vmax

We are given the equation

Vo = (Vmax × [S]) / (Km + [S])

We want to find substrate [S]

Let substitute Vo = ¼Vmax into the given equation, so we have

Vo = (Vmax × [S]) / (Km + [S])

¼ Vmax = (Vmax × [S]) / (Km + [S])

Cross multiply

Vmax × (Km + [S]) = 4 × Vmax × [S] Divide both side by Vmax

(Km + [S]) = 4 × [S]

Km + [S] = 4•[S]

Make [S] subject of formula

4•[S] — [S] = Km

3•[S] = Km

Divide both sides by 3

[S] = Km / 3

[S] = ⅓ Km

So the substrate [S] is ⅓ Km when Vo is ¼Vmax

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b

he can buy 4lbs. of live bait and 1lbs of natural bait

step-by-step explanation: