Assume that women's heights are normally distributed with a mean given by mu equals 64.5 in, and a standard deviation given by sigma equals 2.3 in.
(a) If 1 woman is randomly selected, find the probability that her height is less than 65 in.
(b) If 46 women are randomly selected, find the probability that they have a mean height less than 65 in.

Given that Haruka hiked only 25% less in the afternoon, this means that in the afternoon she hikes 75% of the distance she hiked in the morning. This 75% of a certain number is equal to 6. To determine the distance she hiked in the morning, we represent it as x and use the equation,

            0.75x = 6

The value of x from the equation is 8. Adding together the 6 and 8 will give us an answer of 14.

14 kilometers

Step-by-step explanation:

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jml angle lkj & angle mj = lm