The weight of a single bag checked by an airplane passenger follows a distribution that is right skewed with a mean of 38 pounds and a standard deviation of 6.2 pounds. If a random sample of 96 bags is selected, what is the probability that the average weight of the bags exceeds 40 pounds?

0.0007872

Step-by-step explanation:

-Since the sample size is large enough, we apply the normal distribution to find the probability.

#Given n=96, mean=38 and standard deviation=6.2 pounds, the probability can be calculated as:

Hence, the probability is 0.0007872

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632