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Mathematics, 24.04.2020 18:24 nails4life324

In this problem you will calculate the area between f(x)=x2f(x)=x2 and the xx-axis over the interval [1,8][1,8] using a limit of right-endpoint Riemann sums: Area=limn→[infinity](∑k=1nf(xk)Δx). Area=limn→[infinity](∑k=1nf(xk)Δx). Express the following quantities in terms of nn, the number of rectangles in the Riemann sum, and kk, the index for the rectangles in the Riemann sum. We start by subdividing [1,8][1,8] into nn equal width subintervals [x0,x1],[x1,x2],…,[xn−1,xn][x0,x1], [x1,x2],…,[xn−1,xn] each of width ΔxΔx. Express the width of each subinterval ΔxΔx in terms of the number of subintervals nn. Δx=Δx= Find the right endpoints x1,x2,x3x1,x2,x3 of the first, second, and third subintervals [x0,x1],[x1,x2],[x2,x3][x0,x1],[x1, x2],[x2,x3] and express your answers in terms of nn. x1,x2,x3=x1,x2,x3= (Enter a comma separated list.) Find a general expression for the right endpoint xkxk of the kth subinterval [xk−1,xk][xk−1,xk], where 1≤k≤n1≤k≤n. Express your answer in terms of kk and nn. xk=xk= Find f(xk)f(xk) in terms of kk and nn. f(xk)=f(xk)= Find f(xk)Δxf(xk)Δx in terms of kk and nn. f(xk)Δx=f(xk)Δx= Find the value of the right-endpoint Riemann sum in terms of nn. ∑k=1nf(xk)Δx=∑k=1nf(xk)Δx= Find the limit of the right-endpoint Riemann sum. limn→[infinity](∑k=1nf(xk)Δx)=limn→ [infinity](∑k=1nf(xk)Δx)=

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