One edge of a painting is 6 in. longer than the shorter edge. The picture has a 2-in.-wide frame.
Part A
Which quadratic function represents the total area of the picture and frame?
Part B
What is the total area of the framed picture if its shorter edge is 8 inches long?
Enter your answer in the box.

Part A). (L² + 14L + 40) Square inches

Part B). 216 square inches

Step-by-step explanation:

From the figure attached,

Length of the shorter edge of the painting = L in.

Length of the longer edge of the painting = (L + 6) in.

Part -A)

Length of the shorter edge of the painting plus frame = (L + 4) in.

Length of the longer edge of the painting plus frame = (L + 6 + 4)

                                                                                        = (L + 10) in.

Total area of the picture and frame = (Shorter edge)×(longer edge)

A = (L + 4)(L + 10)

A = L(L + 10) + 4(L + 10)

A = L² + 10L + 4L + 40

A = (L² + 14L + 40) Square inches

Part B)

Total area of the framed picture if L = 8 inches

Area = (8)² + 14(8) + 40

        = 64 + 112 + 40

        = 216 square inches

Therefore, area of the framed picture is 216 square inches.

0.6

39mph

step-by-step explanation:

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic