Mathematics, 24.04.2020 16:28 StephenSudu

2 start fraction, 2, divided by, 12, end fraction and 76\dfrac{7}{6} 6 7 start fraction, 7, divided by, 6, end fraction by first comparing each fraction to 12\dfrac{1}{2} 2 1 start fraction, 1, divided by, 2, end fraction and 11 1 1 . Step 1: 212\dfrac{2}{12} 12 2 start fraction, 2, divided by, 12, end fraction is less than 12\dfrac{1}{2} 2 1 start fraction, 1, divided by, 2, end fraction . Step 2: 76\dfrac{7}{6} 6 7 start fraction, 7, divided by, 6, end fraction is less than 11 1 1 but more than 12\dfrac{1}{2} 2 1 start fraction, 1, divided by, 2, end fraction . Step 3: So, 212<76\dfrac{2}{12} < \dfrac{7}{6} 12 2 < 6 7 start fraction, 2, divided by, 12, end fraction, is less than, start fraction, 7, divided by, 6, end fraction In which step did Tom make his first mistake?

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2 start fraction, 2, divided by, 12, end fraction and 76\dfrac{7}{6} 6 7 start fraction, 7, divide...