A spinner of 10 divisions, numbered from 1 to 10, is spun and two coins are tossed. What is the probability to land on a prime number in the spin and getting two tails from the two tosses?

1/10

Step-by-step explanation:

There are 4 prime numbers from 1 to 10 (2,3,5,7). This makes the probability of getting a prime number as 4/10 = 2/5.

The probability of getting one tail is 1/2, making the proability of getting 2 to be (1/2)^2 = 1/4.

Multiply both probabilities together, and you get 2/5 * 1/4 = 1/10

y = 2x

step-by-step explanation:

if you divide each number in the sequence, you'll see that they all have a multiple factor of 2. each number in the series, and any other numbers which may continue, will be multiplied by 2. therefore, y is the next number in the sequence, and x is the current one, so, our formula will be y = 2x.