C is the incenter of isosceles triangle ABD with vertex angle
ABD. Does the following proof correctly justity that triangles ABC and DBC are congruent?
1. It is given that is the incenter of triangle ABD, so segment BC is an altitude of angle ABD.
2. Angles ABC and DBC are congruent according to the definition of an angle bisector
3. Segments AB and DB are congruent by the definition of an isosceles triangle
4. Triangles ABC and DBC share side BC, so it is congruent to itself by the reflexive property
5. By the SAS postulate, triangles ABC and DBC are congruent
There is an error in line 1. segment BC should be an angle bisector,
The proot is correct
There is an error in line 3. segments AB and BC are congruent
Theresantno in ne 5, the ASA Postulate should be used

answer: the proof is mentioned below.

step-by-step explanation:

since, given:   lines bc = ef

prove:   lines ac > ef

          statements                                           reason

1. bc=ef                                           1. given

2. ac= ab+bc                                 2. because b is the point between the  

                                                            line segment ac

3.   ac > bc                                       3. because if a line segment is equal to

                                                          the sum of two line segments then it is

                                                          always greater then each of these

                                                          individual line segments

4. ac > ef                                         4. by equality property.

2x=70  

x=70/2

x=35

thats the answer

step-by-step explanation:

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