A common mathematical pattern starts as 1, 1, 2, 3, 5, ... The first two terms are both equal to 1 and after that, each number in the sequence is the sum of the two numbers immediately before it. That is, the third term in the sequence is 2 (since that equals 1 + 1), the fourth term is 3 (since that equals 1 + 2), and the fifth term must be 2 + 3, which equals 5. Therefore, the first five terms in the sequence (called the "Fibonacci Sequence") are 1, 1, 2, 3, and 5. What is the 12th term of the sequence?

144

Step-by-step explanation:

1,1,2,3,5,8,13,21,34,55,89,144

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.