The holding tanks are congruent in size, and both are in the shape of a cylinder that has been cut in half vertically. The bottom of the tank is a curved surface. What is the volume of both tanks if the radius of tank #1 is 35 feet and the height of tank #2 is 120 feet? You must explain your answer using words, and you must show all work and calculations to receive credit. (2 points)

16800 feet

Step-by-step explanation:

If the two cylinders were at one point a whole since they were cut together, you would multiply 35 and 120 by 2, getting you 70 and 240. You then multiply those two numbers, getting you 16800 feet. Im probably wrong idk.

well we know there are 4 clubs in 52 cards so it’s replaced so it should be 3/51

step-by-step explanation:

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)