Segments PR and QT are diameters of Circle A.
Find the mPRU
A. 220
B. 40
C. 320
D. 270

C. 320

Step-by-step explanation:

Given:

As we can see in the photo, PR and QR are perpendicular with each other at the angle PAQ => the angle QAR = 90°

=> arc PR = 360°/2 = 180°

=> mTAU = 180° - mRAS -mSAT - mPAU = 180° - 50° + 40° + 40° = 50°

Hence,  mPRU = mRAS + mSAT + mTAU + arc PQ

= 50° + 40° + 50° + 180°

= 320°

the answer is 15% decrease

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: