Indicate the equation of the given line in standard form.
The line that contains the point Q[1,-2) and is parallel to the line whose equation is
y-4 = 2/3 (x-3)
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Step-by-step explanation:

Hello:

equation is the line is : y = ax+b        a is a slope

y = (2/3)x+b   ( same slope for the line : y-4 =2/3(x-3) because are parallel)

passing through the point Q(1;−2) :   -2 =(2/3)(1)+b   so b= -2-2/3 = - 8/3

y = (2/3)x-8/3

The eqiation of the line is y = (2/3)x - 8/3.

Step-by-step explanation:

When the question says a line is parallel to the other line, their gradient must be the same not the equation. So you have to find the gradient of the new equation using the equation that is shown in the question :

y - 4 = 2/3(x-3)

y - 4 = (2/3)x - 2

y = (2/3)x + 2

m = 2/3

We have already found the gradient. Next, you just have to substitute Q-coordinates into the slope-form equation, y = mx+b, to find the value of b :

y = mx + b

m = 2/3

At Q(1,-2),

-2 = 2/3(1) + b

b = -2 - 2/3

= -8/3

im alright what do you need

step-by-step explanation: