What is the length of the hypotenuse x if (12,32,x) is a pythagorean triple ?

approximatly 34.18

Step-by-step explanation:

so we know that a^2 + b^2 = c^2

so knowing we are finding the hypotenuse ( longest side of the triangle ), we are solving for c!

so now lets fill in the equation:

12^2 + 32^2 = c^2

so now lets break it down

12^2=144 & 32^2= 1,024

fill in the equation: 144 + 1,024 = 1,168

now just find the square root of 1,168!

which is approximatly: 34.18!!

i really hope this helped <3

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct

the answer is 8.64

step-by-step explanation: