The opening in a rectangular door frame measures 9 feet by 3 feet. Each of the four doors described in the table measures 9
feet by 3 feet, but have different diagonal lengths. Which door will fit in the rectangular opening?
Door 1
Door 2
diagonal: 10 feet
Door 3
diagonal 3 V10 feet
Door 4
diagonal: 6
feet
diagonal: 12 feet
Door 1
Door 2
Door 3
Door

  Door 3  diagonal 3√10 feet

Step-by-step explanation:

The diagonal of a rectangle is the hypotenuse of a right triangle whose legs are the side lengths of the rectangle. That is, the diagonal of a 9 ft by 3 ft rectangle will have length ...

  d = √(9² +3²) = √90 = 3√10

Any "9 ft by 3 ft" figure that has a diagonal different from this is not a rectangle. To fit the rectangular opening, we want a rectangular door—one with a diagonal of 3√10 feet.

Door 2

Step-by-step explanation:

i think 5 miles per hour

step-by-step explanation:

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .