The cost of producing x bags of dog food is given by C(x) = 800 + 400 + 10x - x where 0 SX 55000. Find the marginal-cost function.

The marginal-cost function is c'(x)=

(Use integers or fractions for any numbers in the expression.)

The marginal-cost function is;

c'(x)= (20x-1)/(2√(400 + 10x² - x))

Completed question;

The cost of producing x bags of dog food is given by C(x) = 800 + √(400 + 10x² - x) where 0≤x≤55000. Find the marginal-cost function.

The marginal-cost function is c'(x)=

(Use integers or fractions for any numbers in the expression.)

Step-by-step explanation:

The marginal-cost function is c'(x)= = dC(x)/dx

Where;

C(x) = 800 + √(400 + 10x² - x)

c'(x) = d(800 + √(400 + 10x² - x) )/dx

Using function of function rule of differentiation or chain rule;

c'(x) = (20x-1)×(1/2√(400 + 10x² - x))

c'(x) = (20x-1)/(2√(400 + 10x² - x))

The marginal-cost function is;

c'(x)= (20x-1)/(2√(400 + 10x² - x))

step-by-step explanation:

i could only see the first page. the other pages were blurry. ; -;

x hot dogs for 2$, y drinks for 3$. 29 items and total 70

2x+3y=70

x+y=29

if x=17and y=12

2(17)+3(12)=70

34+36=70