Hey there, Lets solve this problem together.Â
You are given two lengths of a right angled triangle, so Pythagoras' theorem is the way to go.Â
In algebraic terms, a² + b² = c² where c is the hypotenuse while a and b are the legs of the triangle.Â
In a right angled triangle:
the square of the hypotenuse is equal to
the sum of the squares of the other two sides.
c² (the diagonal squared) = a² (one length squared) + b² (the other length squared) Â
leg a and b are both 3Â
![3^2 + 3^2 = c^2 ](/tpl/images/0374/3541/234d2.png)
![= 3 * 3 = 3^2 ](/tpl/images/0374/3541/09196.png)
![= 9 + 9 = c^2](/tpl/images/0374/3541/e500a.png)
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![9 + 9 =18](/tpl/images/0374/3541/428b2.png)
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![18 = c^2](/tpl/images/0374/3541/b79eb.png)
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The opposite of ^2 is ^1/2 also known as the square root
c = sqrt(18)
Solved = c≈4.24Â