The score of golfers for a particular course follows a normal distribution that has a mean of 73 and a standard deviation of 3. Suppose a golfer played the course today. Find the probability that her score is at least 74.

0.3694

Step-by-step explanation:

In this question, we are asked to calculate the probability that a golfer scored at least 74 if she played on a particular day.

Given that ,

mean = µ = 73

standard deviation = σ = 3

P(x > 74) = 1 - P(x<74 )

= 1 - P[(x -µ) / σ < (74 -73) /3 ]

= 1 - P(z <0.3333 )

Using z table

= 1 - 0.6305

= 0.3694

probability= 0.3694

1,645,493,059.35

step-by-step explanation:

9 x 8 divided by (5-3)=36