Mathematics, 22.04.2020 22:05 sierrawalk3896
The graphed line shown below is y = negative 4 x minus 12.
On a coordinate plane, a line goes through (negative 3, 0) and (negative 2, negative 4).
Which equation, when graphed with the given equation, will form a system that has no solution?
y = 4 x + 12
y = negative 4 x
y = negative 12
y = negative 4 (x + 3)
Answers: 1
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The graphed line shown below is y = negative 4 x minus 12.
On a coordinate plane, a line...
On a coordinate plane, a line...
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