A teacher decides to purchase a new car and considers two options. Option one is the new Zoomba for $60,000 with an expected depreciation of 2% per month. Option two is the new Starfish for $40,000 with an expected depreciation of $200 per month. The teacher plans to keep the car for two years and chooses the option that is expected to retain the most value. Which option did the teacher choose (exponential or linear), and what was the value of the chosen option after two years?

A) The teacher chose the linear option with an expected value of $35,200.
B) The teacher chose the linear option with an expected value of $36,946.82.
C) The teacher chose the exponential option with an expected value of $35,200.
D) The teacher chose the exponential option with an expected value of $36,946.82.

option: d is correct

step-by-step explanation:

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

-12 > a

step-by-step explanation:

-11 > 1 + a

subtract 1 from each side

-11 -1> 1 -1+ a

-12 > a