Four friends are racing. Lisa finishes four hours ahead of Tony, with Pete finishing eight hours ahead of Max. Max needed six more hours to finish than Lisa. What order do they cross the finish line in?

Need steps. Please

Pete, Lisa, Tony, Max

Step-by-step explanation:

Lisa is 4 ahead Tony, putting Tony 4 behind Lisa

Pete is 8 ahead Max, putting Max 8 behind Pete

Lisa is also 6 ahead Max, putting Max 6 behind Lisa

So, Pete is 8 ahead Max, but lisa is 6 ahead Max, so Pete is ahead of Lisa by 2

Then lisa is 4 ahead Tony, so tony is 4 behind lisa and 6 behind Pete

Therefore (I know its confusing) The order is Pete, Lisa, Tony, Max

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752