H(x)=x 2 −1h, left parenthesis, x, right parenthesis, equals, x, squared, minus, 1 Over which interval does h hh have a negative average rate of change? Choose 1 Choose 1 (Choice A) A − 3 ≤ x ≤ 5 −3≤x≤5minus, 3, is less than or equal to, x, is less than or equal to, 5 (Choice B) B 1 ≤ x ≤ 4 1≤x≤41, is less than or equal to, x, is less than or equal to, 4 (Choice C) C − 3 ≤ x ≤ 1 −3≤x≤1minus, 3, is less than or equal to, x, is less than or equal to, 1 (Choice D) D − 1 ≤ x ≤ 5 −1≤x≤5minus, 1, is less than or equal to, x, is less than or equal to, 5 Show Calculator

(C)−3 ≤ x ≤ 1

Step-by-step explanation:

The average rate of change of function h over the interval , is given by this expression:

Given the function on the interval:− 3 ≤ x ≤ 1

The average rate of change:

Therefore, the function has a negative average rate of change over the interval − 3 ≤ x ≤ 1.

CHECK:

(A)Average rate of change of h(x) over the interval − 3 ≤ x ≤ 5=2

(B)Average rate of change of h(x) over the interval 1 ≤ x ≤ 4=5

(D)Average rate of change of h(x) over the interval − 1 ≤ x ≤ 5=4

you can not drow on this

step-by-step explanation:

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b