Write a vector equation of the line that passes through point (1,5) and is parallel to a =(-7,2) then write
parametric equations of the line.

vector equation:

<x2+7, y2-2> = t <-7,2>

3 variable parametric equations:

x= -7t + 7

y= 2t + (-2)

Step-by-step explanation:

given the vector of a = <-7,2> we know that a1 will be -7 and a2 will be 2.

The point (1,5) gives us our x1 and y1 to plug into the vector equation. So we plug it into <x2 - x1, y2 - y1> = t <a1, a2> and get <x2+7, y2-2> = t <-7,2>. We then use the same x1, y1, a1, and a2 and plug into the 3 variable parametric  equations or x= x1+ ta1 and y= y1 + ta2 to get working equations of x = -7t + 7 and y= 2t + (-2).

the answer is two. hope this !