The lifetime of a certain type of battery is normally distributed with mean value 11 hours and standard deviation 1 hour. There are nine batteries in a package. What lifetime value is such that the total lifetime of all batteries in a package exceeds that value for only 5% of all packages?

The required lifetime value is 11.27.

Step-by-step explanation:

Since we have given that

Mean value = 11 hours

Standard deviation = 1 hour

The total lifetime of all batteries in a package exceeds that value for only 5% of all packages.

So, α = 0.95, z= 1.645

n = 9

So, the lifetime value would be

Hence, the required lifetime value is 11.27.

b.my answer is b.

brainliest

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.