Paris used a simulation to take two random samples of fish in a pond. Her sample size was 30, and the table shows the frequency of each fish in the sample. Paris used the two samples to predict that the average number of trout will be 6, the average number of catfish will be 5, and the average number of bass will be 18.

A 3-column table with 3 rows. Column 1 is labeled Fish type with entries brook trout, catfish, smallmouth bass. Column 2 is labeled Frequency Sample 1 with entries 12, 5, 13. Column 3 is labeled Frequency sample 2 with entries 1, 6, 23.

i dont know

step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

the above table 1 will calculate the population size (n) after a certain length of time (t). all you need to do is plug in the initial population number (no), the growth rate (r) and the length of time (t). the constant (e) is already entered into the equation. it stands for the base of the natural logarithms (approximately 2.71828). growth rate (r) and time (t) must be expressed in the same unit of time, such as years, days, hours or minutes. for humans, population growth rate is based on one year. if a population of people grew from 1000 to 1040 in one year, then the percent increase or annual growth rate is 40/1000 x 100 = 4 percent.

step-by-step explanation:

wow ok so the answer is 1k or just k

because of combining like terms xd