The function g(x) = 5x2 – 10x written in vertex form is g(x) = 5(x – 1)2 – 5. the function g(x) is shown on the graph along with the parent function, f(x) = x2. which statement is true concerning the vertex and the axis of symmetry of g(x)?

The general vertex form of the a quadratic function is y = (x - h)^2 + k. In this form, the vertex is (h,k) and the axis of symmetry is x = h. Then, you only need to compare the vertex form of g(x) with the general vertex form of the parabole to conclude the vertex point and the axis of symmetry. g(x) = 5(x-1)^2 - 5 => h = 1 and k = - 5 => theis vertex = (1, -5), and the axis of symmetry is the straight line x = 1. the vertex is (1,-5) and the symmetry axis is x = 1.

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12