Maritza rolls two number cubes that are numbered 1 through 6. What is the probability that the total on both cubes will be a prime number?

50% Chance

1/2

Step-by-step explanation: 2,3, and 5 are the prime numbers 1-6. That means 3/6 of those numbers are prime. 3/6 simplifies to 1/2 or 50%

5/12 or 41.66666% or 42%

Step-by-step explanation:

There are two number cubes both listed as 1-6. In order to find the probability of the total on both cubes being a prime number, you'd have to first come up with the prime numbers possible by addition. You should get 2, 3, 5, 7, and 11.

After finding the numbers possible, you have to find each of the different number combinations that you could use to get there. You should get 15 different possibilities.

2:

1, 1

3:

1, 2

2, 1

5:

1, 4

4, 1

2, 3

3, 2

7:

1, 6

6, 1

2, 5

5, 2

3, 4

4, 3

11:

5, 6

6, 5

Now, you have to find the total possibilities. You should get 36.

1, 1

1, 2

1, 3

1, 4

1, 5

1, 6

2, 1

2, 2

2, 3

2, 4

2, 5

2, 6

3, 1

3, 2

3, 3

3, 4

3, 5

3, 6

4, 1

4, 2

4, 3

4, 4

4, 5

4, 6

5, 1

5, 2

5, 3

5, 4

5, 5

5, 6

6, 1

6, 2

6, 3

6, 4

6, 5

6, 6

Now all you have to do is divide the two numbers (15 and 36), and you should get 5/12 as an exact answer, or 41.66666 (repeating) %, which you can round up to 42%.

may i see the picture? it would a lot, xox

sample answer: you can determine whether each element of the domain is paired with exactly one element of the range. for example, if given a graph, you could use the vertical line test; if a vertical line intersects the graph more than once, then the relation that the graph represents is not a function.