What is the solution to the system of equations 2x + 3y = 40 and y = x + 10?
x = 2; y = 12

x = 4; y = 14

x = 12; y = 2

x = 14; y = 4

x=2, y=12

STEP BY STEP-

Replace the Y in 2x+3y=40 for X+10, because y=x+10. You now have 2x+3(x+10)=40. Now multiply the X and the 10 by 3, so you have 2x+3x+30=40. Combine like terms to get 5x+30=40. Subtract the 30 on both sides so you get 5x=10. Divide by 5 and that gives you the solution for X (2). Then, plug 2 in for X in the equation y=x+10. You now have Y=2+10. Combine like terms and you get 12, so Y=12.

Sorry that I'm so bad at explaining things

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step-by-step explanation:

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