Assume that when adults with smartphones are randomly selected, 46% use them in meetings or classes. If 9 adult smartphone users are randomly selected, find the probability that exactly 3 of them use their smartphones in meetings or classes.

0.2027 is the probability that exactly 3 out of 9 adults use their smartphones in meetings or classes.

Step-by-step explanation:

We are given the following information:

We treat adult using smartphones in meetings or classes as a success.

P(Adult using smartphone) = 46% = 0.46

Then the number of adults follows a binomial distribution, where

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 9

We have to evaluate:

0.2027 is the probability that exactly 3 out of 9 adults use their smartphones in meetings or classes.

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.