If Ricky has 3 times as many nickels as dimes and they have a combined value of 150 cents, how many of
each coin does he have?

6 dimes and 18 nickels

Step-by-step explanation:

Pick two variables to represent the number of nickels and dimes Ricky has.

Let's say n = number of nickels and d = number of dimes.

Ricky has 150 cents total. Since one nickel is worth 5 cents, and one dime is worth 10 cents, their value in cents would be 5n and 10d. So, 150 = 5n + 10d.

Since Ricky has three times as many nickels as dimes, n = 3d. So, 150 = 5(3d) + 10d.

From there, you have to solve for d first.

150 = 5(3d) + 10d = 15d + 10d = 25d

150/25 = 25d/25

6 = d

Then, plug it back in for the value of n.

150 = 5n + 10(6) = 5n + 60

150 - 60 = 5n + 60 - 60

90/5 = 5n/5

18 = n

Ricky has 6 dimes and 18 nickels.

2y+y=5

add 2y and y