Find the smallest perimeter and the dimensions for a rectangle with an area of 36 in squared. The smallest perimeter for a rectangle with an area of 36 in squared is nothing in. (Simplify your answer.) The dimensions of this rectangle are nothing in. (Simplify your answers. Use a comma to separate answers.)

The dimensions of the rectangle are:

The smallest perimeter therefore will be:

Step-by-step explanation:

Let the dimension of the rectangle be x and y

Area of the Rectangle = xy

Area=36 Inch Squared

Therefore: xy=36

Perimeter of the Rectangle, P(x,y)=2(x+y)

Substituting into P(x,y)

The minimum value of the perimeter occurs at the point where the derivative =0.

Recall:

The dimensions of the rectangle are:

The smallest perimeter therefore will be:

you should at least use a calculater

step-by-step explanation:

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm