A school is painting its logo in the shape of a triangle in the middle of its sports field. The school wants the height of a triangle to be 4 feet. The area of the logo must be less than 12 ft.². Write an inequality that describes a possible base length (in feet) of the triangle. Use b for the base length of the triangular logo.

Step-by-step explanation:

We know that the area of a triangle is given by :-

\text{A}=\dfrac{1}{2}\times Base\times Height

Let b be the base (in feet)  of the triangle .

it is given that  , The school wants the height of the triangle to be 6 feet.

Then, the area of triangle will be :-

\text{A}=\dfrac{1}{2}\times b\times 6=3b            (1)

The area of the logo must be at most (less than or equal to) 15 square feet.

i.e. Area ≤ 15 square feet         (2)

Now, Substitute the value of A from (1) into (2) , we get

3b\leq15

Divide both sides by 3  , we get

b\leq5

Hence, the inequality that describes the possible base lengths (in feet) of the triangle :

b\leq5

hope it helps

180 square centimeters

step-by-step explanation:

17   x 256=4352

sorry if this is wrong, i'm new.

step-by-step explanation: