Find the rational zeros of the polynomial function. Then enter the function in factored form.
h(x)=6x^3-11x²-3x + 2.
The zeros are x __,__,__

The zeros are -1/2, 1/3 and 2.

The factors are (x - 2)(3x - 1)(2x + 1)

Step-by-step explanation:

h(x)= 6x^3 - 11x² - 3x + 2 = 0

As the last term is 2 we try  to see if +/-1 or +/- 2 are zeros

f(1) = -6, f(-1) = -18  so  they are not zeros.

f(2) = 6*8 - 11*4 - 3(2) + 2

= 48 - 44 - 6 + 2

=  4 - 6 + 2

= 0.  

So x = 2 is a zero and x - 2 is a factor.

Dividing by x - 2:

x - 2 ) 6x^3 - 11x² - 3x + 2 ( 6x^2 + x - 1 <Quotient

         6x^3  - 12x^2

                      x^2 - 3x

                      x^2 - 2x

                             - x+ 2

                             -x + 2

Factoring the quotient:

6x^2 + x - 1

= (3x - 1)(2x + 1) =  0

x = 1/3, x = -1/2..

the 8 in 8,420 is in the thousands place so it's value is 8 thousand.

the 8 in 6,870 is in the hundreds place so it's value is 8 hundred.

divide 8000 by 800 to find the answer:

8000 / 800 = 10

the 8 in 8,420 is 10 times greater than the 8 in 6,870

well if he bought them at 5 cedis each sold them at 7 cedis each then he would make a profit of 2 cedis of each book. if in total he made 150 cedis profit that means he sold 75 books. he lost 12 books at the start so that means he originally bought a total of 82 books.

step-by-step explanation: