An object is dropped from 43 feet below the tip of the pinnacle atop a 527-ft tall building. The height h of the object after t seconds is given by the equation h equals negative 16 t squared plus 484. Find how many seconds pass before the object reaches the ground.

5.5 seconds

Step-by-step explanation:

The function that gives the height of the object after t seconds falling is:

h = -16t^2 + 484.

To find the time when the object reaches the ground, we just need to use the value of h = 0 in the equation, and then find the value of t:

0 = -16t^2 + 484.

16t^2 = 484

t^2 = 30.25

t = 5.5 seconds

So the object will reach the ground after 5.5 seconds

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation:

i need more details sorry

step-by-step explanation: