A can contains 40 chips: 10 each of read and blue, 12 pink, and the remaining black. If Susan were to remove 3 black and 2 red chips, what is the probability that next one she removes is black? Please Help!

1:7

Step-by-step explanation:

R = RED | B = BLUE | P = PINK | BL = BLACK | c = chips

10R + 10B + 12P = 32 chips

40c - 32c = 8 black chips

8BL - 3BL = 5 black chips

10R - 2R = 8 red chips

2R + 3BL = 5 chips

40c - 5c = 35 chips

5BL : 35c = 1:7

answer: a rhombus has two lines of symmetry that run through one vertex to the one directly across it. unlike a square, planes through the center of each edge of a rhombus do not yield mirrored sides.

step-by-step explanation:

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )