A box is created from a square piece of cardboard 6 in. on a side by cutting a square from each corner and folding up the sides. Let x represent the length of the sides of the squares removed from each corner. box Write a function representing the volume of the box, V(x). Write as a polynomial in standard form. Note: To write a polynomial in standard form, remember, you must multiply everything out.

The function which represents the volume of the box

V(x)=4x³-24x²+36x

where V(x) is in cubic inches.

Step-by-step explanation:

Cuboid:

Given that,

The dimensions of the cardboard is  6 inches by 6 inches.

The length of the side of the squares that removed from each corners of the cardboard is represented by x.

Then, the length of the box is = (6-2x) inches.

The width of the box is = (6-2x) inches

The height of the box is = x inches.

The volume of the box is= length ×width× height

                                         =(6-2x)(6-2x) x cubic inches

                                         ={6(6-2x)-2x(6-2x)}x cubic inches

                                        ={36-12x-12x+4x²}x cubic inches

                                        ={36-24x+4x²}x cubic inches

                                        =(36x-24x²+4x³) cubic inches

                                        =(4x³-24x²+36x) cubic inches

The function which represents the volume of the box

V(x)=4x³-24x²+36x

where V(x) is in cubic inches.

45

step-by-step explanation:

30+15

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer