Use the given conditions to write an equation for the line in point-slope form and in slope-intercept form.
Passing through (7,1) with x-intercept -5
Write an equation for the line in point-slope form...
WILL GIVE BRAINLIEST!!!

Step-by-step explanation:

Point-slope form is: , where (x_1, y_1) is the point given and m is the slope.

The problem gives us two points, actually: (7, 1) and (-5, 0); the second one is the x-intercept because x-intercepts always have a y-coordinates of 0. We can use these two points to find the slope, which is just change in y over change in x: . So, the slope = m = 1/12.

Now, we have our point (7, 1) and the slope 1/12, so just plug these into the above format:

Hope this helps!

y - 1 = (1/12)(x - 7)

y = (1/12)(x + 5)

You can use either of these

Step-by-step explanation:

Slope using (-5,0) and (7,1)

m = (0-1)/(-5-7) = -1/-12

m = 1/12

y - 1 = (1/12)(x - 7)

Or,

y - 0 = (1/12)(x - -5)

y = (1/12)(x + 5)

0.85 or 85%

step-by-step explanation:

1) divide 23 by 27

2) round the decimal to the nearest 10

3) so your answer would be 0.85 or 85%

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .