A 16-ft ladder is placed 4 ft. from the base of a
building. How high on the building will the ladder
reach?

You have a right triangle.

a^2+b^2=c^2

4^2+b^2=256

16+b^2=256

b^2=256-16

b^2=240

b=sqrt240

b=15.49 ft. ans. for the height of the ladder up the wall.

Step-by-step explanation:

mk./km: lm

step-by-step explanation:

,mlmlm

; mk

lk

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length