Many variants of poker are played with both cards in players’ hands and shared community cards. Players’ hand are some combination of the two sets of cards. For parts (a) and (b), consider playing such that Anna, Brad, Charlie, and Dre each have 2 cards for themselves, and build a 5 card hand out of those 2 cards and 3 shared cards. Assume a standard 52-card deck is being used.

What is the probability that Anna has a flush, where her 2 cards and the 3 community cards share a suit?

Step-by-step explanation:

Given that Anna has a flush, this means that the three shared cards and the 2 cards with Anna has the same suit, therefore given this condition the probability that Brad also has a flush is computed here as:

= Probability that Brad has the same suit cards as those shared cards and Anna

= Probability that Brad selected 2 cards from the 8 cards remaining of that suit

= Number of ways to select 2 cards from the 8 cards of that same suit / Total ways to select 2 cards from the remaining 47 cards

 = 0.0259

Therefore 0.0259 is the required probability here.

the little calculation is shown in the picture attached

-10i^2-4i

step-by-step explanation:

evaluate for p=2,q=5i

(2−4)(2+5i)i

(2−4)(2+5i)i

=−10i2−4i