Jenelle invested $14600 in two mutual funds Fund A earned 5% profit during the first year, while Fund B suffered a 2.5% loss. If she received a total of $430 profit, how much had she invested in each mutual fund?

Therefore she invested $10600 and $4000 in Fund A and Fund B respectively.

Step-by-step explanation:

Given that,

Jenelle invested $14600 in two mutual funds.

Fund A 5% profit during the first year.

Fund B suffered a  2.5% loss.

Let she invested $x in Fund A.

Then the amount of remaining money is =$(14600-x)

So, she invested $(14600-x) in fund B.

Since Fund A 5% profit during the first year.

The amount of profit from fund A is

= Invest amount in fund A × 5%

=

Since Fund B suffered a  2.5% loss.

The amount of loss in fund B is

=Invest amount in fund B ×2.5%

=(14600-x)×2.5%

Total profit

= Amount of profit - Amount of loss

According to the problem,

⇒x=10,600

She invested in fund B = $(14600-10600)=$4000

Therefore she invested $10600 and $4000 in Fund A and Fund B respectively.

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

what does x eaqual

step-by-step explanation: