The drama club is selling tickets to their play to raise money for the show's expenses. Each student ticket sells for $8 and each adult ticket sells for $12. There was a total of $960 in revenue from the sale of 100 total tickets. Graphically solve a system of equations in order to determine the number of student tickets sold, x, x, and the number of adult tickets sold, y.

Step-by-step explanation:

The drama club is selling tickets to their play to raise money for the show's expenses.

Let the student ticket be represented as x and adult ticket as y

Cost of student ticket,x = $8

Cost of adult ticket,y = $12

The total number of tickets, x + y = 100 ... (1)

There was a total of $960 in revenue from the sale of 100 total tickets.

8x + 12y = 960 ...(2)

Multiplying eq(1) by 8, we get

8x + 8y = 800 ...(3)

Subtract eq (3) from (2), we get

4y = 160

y = 40, sub in eq (1)

x = 60

The no of student ticket, x = 60

The no of adult ticket, y =40

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

55% are girls and 45% are boys : ) hope this

step-by-step explanation: