Suppose you run n independent simulations of an experiment, and suppose that on each single simulation the chance that the experiment is a success is p. Let X be the proportion of successful experiments among the n experiments in your simulation. You can assume n is sufficiently big to apply CLT. Fill in the blank with a function of n and p, and explain your P(X ∈ p± ) ≈ 0.95

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm