A political candidate has asked his/her assistant to conduct a poll to determine the percentage of people in the community that supports him/her. If the candidate wants a 6% margin of error at a 90% confidence level, what size of sample is needed? Be sure to round accordingly.

The size of sample of 193 is needed.

Step-by-step explanation:

Since we have given that

Margin of error = 6%

At 90% confidence level, z = 1.645

Let p = 0.5

and q = 0.5

( because it is the most conservative estimation).

So, using formula, we get :

Hence, the size of sample of 193 is needed.

30005

yes ok